Last week I acquired a new modem because the old one supplied by the provider was acting strange and I wanted it. The new modem is a Cisco 887VA router equipped with a VDSL2/ADSL2+ interface so that it could replace the previous Fritz!box. A day after I had finished the setup I noticed some unusual things which eventually led to the conclusion that packet fragmentation was occurring. In my search for an answer I learned that the Point-to-Point protocol (PPP) needs 8 bits which need to be subtracted from the default MTU of 1500. So configuring an MTU size of 1492 for the Dialer0 interface and altering the max segment size ‘ip tcp adjust-mss 1452’ on the internal VLAN interface did the trick.
But, then I stumbled upon a service page of my provider stating (in Dutch):
RFC4638 wordt ondersteund op ons netwerk. Dit betekent dat u als klant een MTU van 1500 kunt gebruiken als uw router RFC4638 ondersteunt.
So it’s possible to use a MTU size of 1500 if the router is able to do so. In the past I have played with MTU sized 9000 (called Jumbo frames), so 1512 is a baby.
It took some time to figure out how, but eventually came up with the following:
! interface Ethernet0 mtu 1512 no ip address ! interface Ethernet0.6 encapsulation dot1Q 6 pppoe enable group global pppoe-client dial-pool-number 1 pppoe-client ppp-max-payload 1500 ! interface Dialer0 no mtu 1492 ! interface Vlan2 no ip tcp adjust-mss 1452 !
Want to follow the PPP negotiation proces, then execute to following (in enable mode):
debug ppp negotiation clear ppp all show logging
Time to test!
$ ping -c 3 -s 1472 www.xs4all.nl PING www.xs4all.nl (184.108.40.206) 1472(1500) bytes of data. 1480 bytes from www.xs4all.nl (220.127.116.11): icmp_seq=1 ttl=61 time=6.18 ms 1480 bytes from www.xs4all.nl (18.104.22.168): icmp_seq=2 ttl=61 time=6.23 ms 1480 bytes from www.xs4all.nl (22.214.171.124): icmp_seq=3 ttl=61 time=5.96 ms --- www.xs4all.nl ping statistics --- 3 packets transmitted, 3 received, 0% packet loss, time 2003ms rtt min/avg/max/mdev = 5.966/6.128/6.234/0.116 ms $